Solving Complex Equations with Algebraic Manipulations: Case of ( x^4 - frac{1}{x^4} 23 )

Solving Complex Equations with Algebraic Manipulations: Case of ( x^4 - frac{1}{x^4} 23 )

Algebraic manipulation is a powerful tool in solving complex equations. The problem x4 - frac{1}{x4} 23 is a prime example of such a scenario, and in this article, we will explore a step-by-step method to find the value of ( x - frac{1}{x}^2 ).

Introduction to the Problem

Given the equation:

x4 - frac{1}{x^4} 23

We aim to solve for the value of ( x - frac{1}{x}^2 ). We will use algebraic manipulations to simplify and solve the equation.

Step-by-Step Solution

Let's solve the given equation step by step:

1. **Express ( x^4 - frac{1}{x^4} ) in terms of ( x^2 - frac{1}{x^2} ):

We know that:

( x^4 - frac{1}{x^4} left( x^2 - frac{1}{x^2} right)^2 - 2 )

2. **Let ( y x^2 - frac{1}{x^2} ):

Substituting this, we get:

( y^2 - 2 23 )

3. **Solve for ( y^2 ):

( y^2 25 )

4. **Take the square root of both sides:

( y pm 5 )

Since ( y x^2 - frac{1}{x^2} ) is always positive, we have:

( y 5 )

5. **Relate ( y ) to ( x - frac{1}{x} ):

Notice that:

( x^2 - frac{1}{x^2} left( x - frac{1}{x} right)^2 - 2 )

6. **Let ( z x - frac{1}{x} ):

Thus:

( y z^2 - 2 )

7. **Substitute ( y 5 ):

( 5 z^2 - 2 )

8. **Solve for ( z^2 ):

( z^2 7 )

9. **Thus, the value of ( x - frac{1}{x}^2 ) is:

( x - frac{1}{x}^2 3 )

Welcome to the Generalized Approach

The solution method we used here is a simplified version of a more generalized approach that can be applied to more complex scenarios. Here’s how it works:

1. **Generalized Equality:**

( x^4 - frac{1}{x^4} (x^2 - frac{1}{x^2})^2 - 2 )

2. **Substitute ( y ):

( y^2 - 2 25 )

3. **Calculate ( y ):

( y pm 5 )

4. **Relate ( y ) to ( z ):

( z^2 - 2 7 )

5. **Solve for ( z^2 ):

( z^2 7 )

6. **Thus, the value of ( x - frac{1}{x}^2 ) is:

( x - frac{1}{x}^2 3 )

Conclusion

By using algebraic manipulations, we were able to solve the complex equation ( x^4 - frac{1}{x^4} 23 ) and find that ( x - frac{1}{x}^2 ) equals ( 3 ). This method not only simplifies the process but also offers a way to tackle more intricate algebraic problems.