Understanding the Basics: Solving the 3x4 2 Equation
Introduction: In algebra, solving equations is a fundamental skill. In this article, we will explore the equation 3x4 2, a linear equation, and how to solve it. We'll also delve into the more complex quadratic equation 3x^2 4^2 9x^2 - 24x 16, and how to solve this using both factorization and the quadratic formula.
Solving the Linear Equation 3x 4 2
A linear equation involves a first-degree polynomial and has a single variable. To solve 3x 4 2, follow these steps:
Subtract 4 from both sides of the equation. Divide both sides by 3 to isolate x.Let's solve it step by step:
3x 4 2 3x -2 (Subtract 4 from both sides) x -2/3 (Divide both sides by 3)The solution is x -2/3.
Converting to Quadratic Form
Now, let's look at the quadratic equation 3x^2 4^2 9x^2 - 24x 16. We can use algebraic identities to rewrite this equation.
Using Algebraic Identities
The identity (a b)^2 a^2 2ab b^2 can be applied to both sides of the equation.
Applying this to both sides:
3x^2 4^2 9x^2 - 24x 16 (3x 4)^2 (3x - 4)^2This means (3x 4)^2 (3x - 4)^2. Expanding and simplifying:
9x^2 24x 16 9x^2 - 24x 16 24x -24x 48x 0Thus, x 0.
Solving the Quadratic Equation Using Factorization
Let's now solve the quadratic equation 9x^2 - 24x 16 0 using factorization.
First, expand the right-hand side using the identity (a - b)^2 a^2 - 2ab b^2:
(9x - 16)^2 0 9x - 16 0 9x 16 x 16/9The solution is x 16/9.
Using the Quadratic Formula
The quadratic formula is a powerful tool for solving any quadratic equation of the form ax^2 bx c 0. The formula is:
x (-b ± √(b^2 - 4ac)) / 2a
For the equation 9x^2 - 24x 16 0:
a 9 b -24 c 16First, calculate the discriminant:
D b^2 - 4ac (-24)^2 - 4 * 9 * 16 576 - 576 0
Since the discriminant is zero, there is exactly one solution:
x (-(-24) ± √0) / (2 * 9) 24 / 18 16 / 9
Hence, the solution is x 16/9.
Conclusion: In this article, we solved the simple linear equation 3x 4 2 and then tackled the more complex quadratic equation 3x^2 4^2 9x^2 - 24x 16. By using algebraic identities and the quadratic formula, we can solve a wide range of equations accurately.